With 4 Mg atoms and 4 $\mathrm{O_2}$ molecules in $\mathrm{2Mg + O_2 o 2MgO}$, the limiting reactant is—

Question

With 4 Mg atoms and 4 $\mathrm{O_2}$ molecules in $\mathrm{2Mg + O_2 	o 2MgO}$, the limiting reactant is—

Accepted Answer

Mg

Answer

$\mathrm{O_2}$

Answer

both

Answer

neither

With 4 Mg atoms and 4 O2\mathrm{O_2}O2​ molecules in 2Mg+O2→2MgO\mathrm{2Mg + O_2 \to 2MgO}2Mg+O2​→2MgO, the limiting reactant is—