Hypochlorous acid produced in bleaching powder reaction breaks up to give—

• a$\mathrm{HCl}$ + $\mathrm{[O]}$
• b$\mathrm{H_2}$ + $\mathrm{Cl_2}$
• c$\mathrm{H_2O}$ + $\mathrm{Cl_2}$
• d$\mathrm{HClO_3}$