For the reaction $\ce{CH4 + Cl2 - CH3Cl + HCl}$ given $\ce{C-H}=414$, $\ce{Cl-Cl}=244$, $\ce{C-Cl}=326$, $\ce{H-Cl}=431

Question

For the reaction $\ce{CH4 + Cl2 -> CH3Cl + HCl}$ given $\ce{C-H}=414$, $\ce{Cl-Cl}=244$, $\ce{C-Cl}=326$, $\ce{H-Cl}=431$ kJ/mol, total energy to break bonds in reactants:

Accepted Answer

658 kJ

Answer

757 kJ

Answer

1080 kJ

Answer

99 kJ

For the reaction CHX4+ClX2→CHX3Cl+HCl\ce{CH4 + Cl2 -> CH3Cl + HCl}CHX4​+ClX2​ given C−H=414\ce{C-H}=414C−H=414, Cl−Cl=244\ce{Cl-Cl}=244Cl−Cl=244, C−Cl=326\ce{C-Cl}=326C−Cl=326, H−Cl=431\ce{H-Cl}=431H−Cl=431 kJ/mol, total energy to break bonds in reactants:

For the reaction $\ce{CH4 + Cl2 -> CH3Cl + HCl}$ given $\ce{C-H}=414$ , $\ce{Cl-Cl}=244$ , $\ce{C-Cl}=326$ , $\ce{H-Cl}=431$ kJ/mol, total energy to break bonds in reactants: