In $\mathrm{Na_2SO_4 + BaCl_2 o BaSO_4{\downarrow} + 2NaCl}$, the precipitate is—

Question

In $\mathrm{Na_2SO_4 + BaCl_2 	o BaSO_4{\downarrow} + 2NaCl}$, the precipitate is—

Accepted Answer

$\mathrm{BaSO_4}$

Answer

$\mathrm{NaCl}$

Answer

$\mathrm{Na_2SO_4}$

Answer

$\mathrm{BaCl_2}$

In Na2SO4+BaCl2→BaSO4↓+2NaCl\mathrm{Na_2SO_4 + BaCl_2 \to BaSO_4{\downarrow} + 2NaCl}Na2​SO4​+BaCl2​→BaSO4​↓+, the precipitate is—