Reaction of dilute $\mathrm{NaOH}$ with metallic nitrates produces precipitates that are—

1. $\mathrm{Al(OH)_3}$ — white
2. $\mathrm{Cu(OH)_2}$ — light blue
3. $\mathrm{Fe(OH)_3}$ — reddish brown

• ai and ii
• bii and iii
• ci and iii
• di, ii and iii