C-05-Q080mediumsingle_mcqমূলদ্বয় α,β\alpha, \betaα,β হলে সমীকরণটি—ax2−(α+β)x+αβ=0x^2 - (\alpha + \beta)x + \alpha\beta = 0x2−(α+β)x+αβ=0bx2+(α+β)x+αβ=0x^2 + (\alpha + \beta)x + \alpha\beta = 0x2+(α+β)x+αβ=0cx2−(α+β)x−αβ=0x^2 - (\alpha + \beta)x - \alpha\beta = 0x2−(α+β)x−αβ=0dx2+(α−β)x+αβ=0x^2 + (\alpha - \beta)x + \alpha\beta = 0x2+(α−β)x+αβ=0