C-09-Q167mediumsingle_mcq1−sin245∘1+sin245∘+tan245∘=?\dfrac{1 - \sin^2 45^\circ}{1 + \sin^2 45^\circ} + \tan^2 45^\circ = ?1+sin245∘1−sin245∘+tan245∘=?a13\dfrac{1}{3}31b43\dfrac{4}{3}3ব্যাখ্যাSince sin245∘=12\sin^2 45^\circ=\tfrac12sin245∘=21 and , the fraction becomes . Adding gives .