C-12-Q085mediumsingle_mcq

If $2x - y = 8$ and $x - 2y = 4$ , then $x + y =$ —

Solving the system: from $x - 2y = 4$ , $x = 4 + 2y$ , so $2 (4 + 2 y) - y = 8 \Rightarrow 3$ and . Hence .

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এই অধ্যায়ের আরও প্রশ্ন

C-12-Q086If and , then —
C-12-Q087The system is —
C-12-Q088If the digit at the tens place is and units place is , the two-digit number is —
C-12-Q089After interchanging the digits of a two-digit number with tens digit and units digit , the new number is —
C-12-Q090In Example 12, the required number is —
C-12-Q091The sum of digits of a two-digit number is and on interchanging the digits the new number exceeds the original
C-12-Q092The units digit of a two-digit number is more than thrice the tens digit, and the interchanged number equals t
C-12-Q093The difference of the digits of a two-digit number is and the sum of the number and its digit-reversal is . Th

12

y

=

0

\Rightarrow

y

=

0

2(4+2y) - y = 8 \Rightarrow 3y = 0 \Rightarrow y = 0

2 (4 + 2 y) - y = 8 \Rightarrow 3 y = 0 \Rightarrow y = 0

x = 4

x + y = 4