C-12-Q043mediumsingle_mcqThe solution (x,y)(x, y)(x,y) of 7x−3y=31, 9x−5y=417x - 3y = 31,\; 9x - 5y = 417x−3y=31,9x−5y=41 is —a(4,1)(4, 1)(4,1)b(4,−1)(4, -1)(4,−1)c(−4,1)(-4, 1)(−4,1)d(2,−1)(2, -1)(2,−1)ব্যাখ্যাEliminating yyy: 5(7x−3y)−3(9x−5y)=5(31)−3(41)5(7x - 3y) - 3(9x - 5y) = 5(31) - 3(41)5(7x−3y)−3(9x−5y)=5(31)−3(41) gives 8x=328x = 328x=32, so x=4x = 4x=4. Then 7(4)−3y=317(4) - 3y = 317(4)−3y=31 yields y=−1y = -1y=−1, giving (4,−1)(4, -1)(4,−1).