C-01-Q070mediumsingle_mcq

$x(x+1)(x+2)(x+3) + 1$ equals—

a $(x^2 + 3x)^2$
b $(x^2 + 3x + 1)^2$
c $(x + 3)^2$
d $(x^2 + 3x + 2)^2$

ব্যাখ্যা

Pairing the outer and inner factors gives $(x^2+3x)(x^2+3x+2)+1$ ; letting $t = x^2+3x$ yields $t(t+2)+1 = (t+1)^2 = (x^2+3x+1)^2$ . This is a perfect square trinomial.

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Real Numbers — সব প্রশ্ন দেখুন (149টি) →

$x(x+1)(x+2)(x+3) + 1$ equals—

(x^2 + 3x)^2

(x^2 + 3x + 1)^2

(x + 3)^2

(x^2 + 3x + 2)^2

ব্যাখ্যা

Pairing the outer and inner factors gives $(x^2+3x)(x^2+3x+2)+1$ ; letting $t = x^2+3x$ yields $t(t+2)+1 = (t+1)^2 = (x^2+3x+1)^2$ . This is a perfect square trinomial.

x(x+1)(x+2)(x+3)+1x(x+1)(x+2)(x+3) + 1x(x+1)(x+2)(x+3)+1 equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

x(x+1)(x+2)(x+3)+1x(x+1)(x+2)(x+3) + 1x(x+1)(x+2)(x+3)+1 equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

$x(x+1)(x+2)(x+3) + 1$ equals—

$x(x+1)(x+2)(x+3) + 1$ equals—