C-14-Q160mediumsingle_mcq

In $\triangle ABC$ , $AD$ bisects $\angle A$ , meets $BC$ at $D$ . If $AB = 7$ , $AC = 5$ , $BC = 12$ , then $BD = ?$

a $5$
b $6$
c $7$
d $\dfrac{12 \cdot 7}{5}$

ব্যাখ্যা

By the angle bisector theorem, $BD:DC=AB:AC=7:5$ , so $BD=\dfrac{7}{12}\times 12=7$ . Splitting $BC=12$ in the ratio $7:5$ assigns $7$ units to $BD$ .

এই অধ্যায়ের আরও প্রশ্ন

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In △ABC\triangle ABC△ABC, ADADAD bisects ∠A\angle A∠A, meets BCBCBC at DDD. If AB=7AB = 7AB=7, AC=5AC = 5AC=5, BC=12BC = 12BC=12, then BD=?BD = ?BD=?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In △ABC\triangle ABC△ABC, ADADAD bisects ∠A\angle A∠A, meets BCBCBC at DDD. If AB=7AB = 7AB=7, AC=5AC = 5AC=5, BC=12BC = 12BC=12, then BD=?BD = ?BD=?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In $\triangle ABC$ , $AD$ bisects $\angle A$ , meets $BC$ at $D$ . If $AB = 7$ , $AC = 5$ , $BC = 12$ , then $BD = ?$

In $\triangle ABC$ , $AD$ bisects $\angle A$ , meets $BC$ at $D$ . If $AB = 7$ , $AC = 5$ , $BC = 12$ , then $BD = ?$