C-14-Q055mediumsingle_mcq

In $\triangle ABC$ , $X$ on $BC$ , $O$ on $AX$ . Then $\triangle AOB : \triangle AOC = ?$

a $AO:OX$
b $BX:XC$
c $AB:AC$
d $1:1$

ব্যাখ্যা

Triangles $AOB$ and $AOC$ share the same vertex $O$ and their bases $OB$ , $OC$ ... actually they share apex $A$ over base segments; with $O$ on $AX$ , both triangles have equal heights from $A$ to line $BC$ , so their areas are in the ratio of bases $BX:XC$ .

এই অধ্যায়ের আরও প্রশ্ন

C-14-Q056Congruence is a special case of —
C-14-Q057Two congruent figures are —
C-14-Q058Two similar figures are —
C-14-Q059Polygons with equal numbers of sides whose angles are sequentially equal are —
C-14-Q060Two polygons are similar when matching angles are equal AND matching sides are —
C-14-Q061A rectangle and a square are equiangular but generally —
C-14-Q062Two equiangular triangles are always —
C-14-Q063Two similar triangles are always —
C-14-Q064If two equiangular triangles have one matching pair of sides equal, they are —
C-14-Q065If two triangles are equiangular, their matching sides are —

In $\triangle ABC$ , $X$ on $BC$ , $O$ on $AX$ . Then $\triangle AOB : \triangle AOC = ?$

AO:OX

BX:XC

AB:AC

1:1

In △ABC\triangle ABC△ABC, XXX on BCBCBC, OOO on AXAXAX. Then △AOB:△AOC=?\triangle AOB : \triangle AOC = ?△AOB:△AOC=?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In △ABC\triangle ABC△ABC, XXX on BCBCBC, OOO on AXAXAX. Then △AOB:△AOC=?\triangle AOB : \triangle AOC = ?△AOB:△AOC=?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In $\triangle ABC$ , $X$ on $BC$ , $O$ on $AX$ . Then $\triangle AOB : \triangle AOC = ?$

In $\triangle ABC$ , $X$ on $BC$ , $O$ on $AX$ . Then $\triangle AOB : \triangle AOC = ?$