C-14-Q041mediumsingle_mcq

In the proof, $\angle ACE = \angle CAD$ because they are —

acorresponding angles
balternate angles
csupplementary
dcomplementary

ব্যাখ্যা

With $CE \parallel AD$ and $AC$ as the transversal, $\angle ACE$ and $\angle CAD$ are alternate (interior) angles, which are equal for parallel lines.

এই অধ্যায়ের আরও প্রশ্ন

C-14-Q042In the proof, because is —
C-14-Q043In , , , . bisects , meets at . Then
C-14-Q044In , , , . If bisects ,
C-14-Q045In , , , . If bisects ,
C-14-Q046If a side of a triangle is divided internally in the ratio of the other two sides, the segment to the opposite
C-14-Q047In Theorem 31, the construction draws parallel to —
C-14-Q048In the proof of Theorem 31, follows from —
C-14-Q049In Theorem 31, is established from —
C-14-Q050Bisectors of two base angles of a triangle meet the opposite sides at and . If base, the triangle is —
C-14-Q051If two transversals cut a set of parallel lines, the matching intercepted segments are —

Ratio, Similarity and Symmetry — সব প্রশ্ন দেখুন (160টি) →

In the proof, ∠ACE=∠CAD\angle ACE = \angle CAD∠ACE=∠CAD because they are —

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In the proof, ∠ACE=∠CAD\angle ACE = \angle CAD∠ACE=∠CAD because they are —

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In the proof, $\angle ACE = \angle CAD$ because they are —

In the proof, $\angle ACE = \angle CAD$ because they are —