C-07-Q128mediumsingle_mcq

Triangle $DEF$ with $DE = DF = 4$ cm and $\angle EDF = 50^\circ$ is—

ascalene
bequilateral
cisosceles
dright-angled

ব্যাখ্যা

Since $DE = DF = 4$ cm, two sides are equal while the apex angle is $50^\circ$ , which makes the triangle isosceles. It is neither equilateral (all sides unequal in length to a third value) nor right-angled.

এই অধ্যায়ের আরও প্রশ্ন

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Practical Geometry — সব প্রশ্ন দেখুন (150টি) →

Triangle DEFDEFDEF with DE=DF=4DE = DF = 4DE=DF=4 cm and ∠EDF=50∘\angle EDF = 50^\circ∠EDF=50∘ is—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Triangle DEFDEFDEF with DE=DF=4DE = DF = 4DE=DF=4 cm and ∠EDF=50∘\angle EDF = 50^\circ∠EDF=50∘ is—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Triangle $DEF$ with $DE = DF = 4$ cm and $\angle EDF = 50^\circ$ is—

Triangle $DEF$ with $DE = DF = 4$ cm and $\angle EDF = 50^\circ$ is—