C-07-Q034mediumsingle_mcq

In $\triangle ABD$ , $AB = DB$ because—

a $\angle ADB = \angle DAB$
b $AB \parallel DE$

ব্যাখ্যা

$\angle DAB = \angle ADB$ by construction, and equal base angles make $\triangle ABD$ isosceles. The sides opposite these equal angles, $AB$ and $D$ , are therefore equal.

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এই অধ্যায়ের আরও প্রশ্ন

C-07-Q035In , because—
C-07-Q036The perimeter in the constructed triangle equals—
C-07-Q037In Construction 3, equals—
C-07-Q038In Example 1, is drawn equal to—
C-07-Q039The angle at is—
C-07-Q040The angle at is—
C-07-Q041The bisectors and of the two angles intersect at—
C-07-Q042After drawing perpendicular bisectors of and , they meet at—
C-07-Q043The base is cut equal to—
C-07-Q044

cit is equilateral

d

BD

is a diameter

B

DB

D B

The angle at measures—

Practical Geometry — সব প্রশ্ন দেখুন (150টি) →

In △ABD\triangle ABD△ABD, AB=DBAB = DBAB=DB because—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In $\triangle ABD$ , $AB = DB$ because—