C-07-Q020mediumsingle_mcq

In the alternate method of Construction 1, line segment $CD$ is bisected by—

aits perpendicular bisector $PQ$
bthe angle bisector at $B$
cthe median from $A$
dthe altitude from $C$

ব্যাখ্যা

The alternate method locates points equidistant from $C$ and $D$ , so the bisecting line is the perpendicular bisector $PQ$ of $CD$ . Every point on $PQ$ is equally distant from the two endpoints, so it cuts $CD$ exactly in half at right angles.

এই অধ্যায়ের আরও প্রশ্ন

C-07-Q021In and , the included angle equals—
C-07-Q022The congruence is established by—
C-07-Q023After joining and in the alternate method, equals—
C-07-Q024In Construction 2 the difference is cut on ray as line segment—
C-07-Q025The angle constructed at in Construction 2 equals—
C-07-Q026In the resulting triangle , the difference equals—
C-07-Q027If the given base-adjacent angle is NOT acute, Construction 2 is—
C-07-Q028In Construction 2, because in —
C-07-Q029Construction 2 essentially differs from Construction 1 in that—
C-07-Q030In Construction 3, on ray the part is cut equal to—

Practical Geometry — সব প্রশ্ন দেখুন (150টি) →

In the alternate method of Construction 1, line segment $CD$ is bisected by—

aits perpendicular bisector

PQ

bthe angle bisector at

B

cthe median from

A

dthe altitude from

C

In the alternate method of Construction 1, line segment CDCDCD is bisected by—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In the alternate method of Construction 1, line segment CDCDCD is bisected by—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In the alternate method of Construction 1, line segment $CD$ is bisected by—

In the alternate method of Construction 1, line segment $CD$ is bisected by—