C-16-Q073mediumsingle_mcq

A diagonal of a rhombus is $10$ m and area is $120$ sq m. The other diagonal is —

Using area $=\tfrac{1}{2}d_1 d_2$ , we get , so m. The given diagonal and area uniquely fix the second diagonal.

73/210

এই অধ্যায়ের আরও প্রশ্ন

C-16-Q074With diagonals m and m, each side of the rhombus is —
C-16-Q075The perimeter of a rhombus with side m is —
C-16-Q076Perimeter of a rhombus is cm and the smaller diagonal is cm. Each side is —
C-16-Q077With perimeter cm and one diagonal cm, the other diagonal is —
C-16-Q078Area of the above rhombus (diagonals and cm) is —
C-16-Q079The area of a trapezium with parallel sides and and perpendicular distance between them is —
C-16-Q080Two parallel sides of a trapezium are cm and cm; the other two sides are cm and cm. The perpendicular distance
C-16-Q081The area of the trapezium with parallel sides cm and other sides cm is —
C-16-Q082Difference between the parallel sides of a trapezium is cm and their perpendicular distance is cm. If area is

\tfrac{1}{2}\times 10 \times d_2 = 120

d_2 = 24