Two sides of a triangle are $26$ m and $28$ m and the area is $182$ sq m. The included angle is —

From $\frac{1}{2}ab\sin C = 182$, we get $\sin C = \frac{2 \cdot 182}{26 \cdot 28} = \frac{364}{728} = \frac{1}{2}$. Thus , since .