C-06-Q152mediumsingle_mcq

Continuing the previous question, the exterior $\angle ACD$ when $BC$ is produced to $D$ equals—

a $100°$
b $120°$
c $130°$
d $140°$

ব্যাখ্যা

The exterior angle of a triangle equals the sum of the two remote interior angles, so $\angle ACD = \angle BAC + \angle ABC = 80° + 50° = 130°$ . Equivalently, it is the supplement of $\angle ACB = 50°$ , giving $180° - 50° = 130°$ .

এই অধ্যায়ের আরও প্রশ্ন

C-06-Q153In a right triangle with legs and , the hypotenuse is—
C-06-Q154In an equilateral triangle, all three medians are—
C-06-Q155The triangle formed by joining the midpoints of the sides of an equilateral triangle is—
C-06-Q156If one side of a triangle is greater than another, the angle opposite the greater side is—
C-06-Q157If one angle of a triangle is greater than another, the side opposite the greater angle is—
C-06-Q158The sum of the lengths of any two sides of a triangle is the third side.
C-06-Q159The difference of the lengths of any two sides of a triangle is the third side.
C-06-Q160Which set of lengths can form a triangle?
C-06-Q161Which set CANNOT form a triangle?
C-06-Q162The sum of any two exterior angles of a triangle is—

Lines, Angles and Triangles — সব প্রশ্ন দেখুন (191টি) →

Continuing the previous question, the exterior $\angle ACD$ when $BC$ is produced to $D$ equals—

100°

120°

130°

140°

Continuing the previous question, the exterior ∠ACD\angle ACD∠ACD when BCBCBC is produced to DDD equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Continuing the previous question, the exterior ∠ACD\angle ACD∠ACD when BCBCBC is produced to DDD equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Continuing the previous question, the exterior $\angle ACD$ when $BC$ is produced to $D$ equals—

Continuing the previous question, the exterior $\angle ACD$ when $BC$ is produced to $D$ equals—