C-13-Q152mediumsingle_mcq1+2+3+⋯+20=?1 + 2 + 3 + \cdots + 20 = ?1+2+3+⋯+20=?a210210210b200200200c190190190d231231231ব্যাখ্যাUsing ∑1nk=n(n+1)2\sum_{1}^{n} k = \frac{n(n+1)}{2}∑1nk=2n(n+1) with n=20n=20n=20: 20⋅212=210\frac{20\cdot 21}{2}=210220⋅21=210.