C-13-Q030mediumsingle_mcqIf a=3a = 3a=3 and d=2d = 2d=2, the nnn-th term of the arithmetic series is —a2n+12n + 12n+1b2n−12n - 12n−1c3n+23n + 23n+2d3n−13n - 13n−1ব্যাখ্যাUsing an=a+(n−1)da_n = a + (n-1)dan=a+(n−1)d with a=3a = 3a=3, d=2d = 2d=2: an=3+(n−1)⋅2=3+2n−2=2n+1a_n = 3 + (n-1)\cdot 2 = 3 + 2n - 2 = 2n + 1an=3+(n−1)⋅2=3+2n−2=2n+1.