C-13-Q007mediumsingle_mcqThe first term of the sequence {n−1n+1}\left\{\dfrac{n-1}{n+1}\right\}{n+1n−1} is —a000b12\dfrac{1}{2}21c111d13\dfrac{1}{3}31ব্যাখ্যাPutting n=1n = 1n=1 into n−1n+1\dfrac{n-1}{n+1}n+1n−1 gives 1−11+1=02=0\dfrac{1-1}{1+1} = \dfrac{0}{2} = 01+11−1=20=0.