C-04-Q139mediumsingle_mcqlogaM⋅logMa=?\log_a M \cdot \log_M a = ?logaM⋅logMa=?alogaM\log_a MlogaMb111c000dlogMa\log_M alogMaব্যাখ্যাSince logMa=1logaM\log_M a = \dfrac{1}{\log_a M}logMa=logaM1, the two factors are reciprocals and their product is 111.