C-04-Q072mediumsingle_mcq(125)−1/3=?(125)^{-1/3} = ?(125)−1/3=?a555b−5-5−5c15\dfrac{1}{5}51d−15-\dfrac{1}{5}−51ব্যাখ্যাSince 125=53125=5^3125=53, (125)−1/3=53⋅(−1/3)=5−1=15(125)^{-1/3}=5^{3\cdot(-1/3)}=5^{-1}=\dfrac{1}{5}(125)−1/3=53⋅(−1/3)=5−1=51. The negative exponent gives the reciprocal of the cube root.