C-04-Q014mediumsingle_mcqaman=?\dfrac{a^m}{a^n} = ?anam=? when m>nm > nm>n, a≠0a \neq 0a=0:aam+na^{m+n}am+nbam−na^{m-n}am−ncan−ma^{n-m}an−mdamna^{mn}amnব্যাখ্যাDividing powers with the same base subtracts the exponents, so aman=am−n\frac{a^m}{a^n} = a^{m-n}anam=am−n when m>nm > nm>n.