C-05-Q152mediumsingle_mcq

Solving $\dfrac{1}{x + 1} + \dfrac{1}{x + 2} = \dfrac{2}{x + 3}$ gives a quadratic whose product of roots equals—

a $0$
b $-2$
c $-1$
d $1$

ব্যাখ্যা

Clearing the denominators by cross-multiplying produces a quadratic in $x$ . By Vieta's formula the product of its roots equals the constant term divided by the leading coefficient, which evaluates to $-1$ .

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Equations in One Variable — সব প্রশ্ন দেখুন (170টি) →

Solving 1x+1+1x+2=2x+3\dfrac{1}{x + 1} + \dfrac{1}{x + 2} = \dfrac{2}{x + 3}x+11​+x+21​=x+32​ gives a quadratic whose product of roots equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Solving 1x+1+1x+2=2x+3\dfrac{1}{x + 1} + \dfrac{1}{x + 2} = \dfrac{2}{x + 3}x+11​+x+21​=x+32​ gives a quadratic whose product of roots equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Solving $\dfrac{1}{x + 1} + \dfrac{1}{x + 2} = \dfrac{2}{x + 3}$ gives a quadratic whose product of roots equals—

Solving $\dfrac{1}{x + 1} + \dfrac{1}{x + 2} = \dfrac{2}{x + 3}$ gives a quadratic whose product of roots equals—