C-08-Q213mediumsingle_mcq

If $O$ is the circumcentre of an equilateral triangle $ABC$ , then $\angle BOC$ equals—

a $30^{\circ}$
b $60^{\circ}$
c $90^{\circ}$
d $120^{\circ}$

ব্যাখ্যা

The central angle is twice the inscribed angle subtending the same arc; here the inscribed angle $\angle BAC = 60^{\circ}$ , so $\angle BOC = 2 \times 60^{\circ} = 120^{\circ}$ . Equivalently, the three central angles divide $360^{\circ}$ equally into three parts of $120^{\circ}$ .

এই অধ্যায়ের আরও প্রশ্ন

Circle — সব প্রশ্ন দেখুন (231টি) →

If $O$ is the circumcentre of an equilateral triangle $ABC$ , then $\angle BOC$ equals—

30^{\circ}

60^{\circ}

90^{\circ}

120^{\circ}

If OOO is the circumcentre of an equilateral triangle ABCABCABC, then ∠BOC\angle BOC∠BOC equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

If OOO is the circumcentre of an equilateral triangle ABCABCABC, then ∠BOC\angle BOC∠BOC equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

If $O$ is the circumcentre of an equilateral triangle $ABC$ , then $\angle BOC$ equals—

If $O$ is the circumcentre of an equilateral triangle $ABC$ , then $\angle BOC$ equals—