C-08-Q200mediumsingle_mcq

In Construction 8, $\angle PAO = 1$ right angle because—

a $\triangle PAO$ is equilateral
bit is the angle inscribed in the semicircle of the auxiliary circle
cof SSS congruence
dof an arbitrary choice

ব্যাখ্যা

Because $PO$ is a diameter of the auxiliary circle, $\angle PAO$ is an angle inscribed in a semicircle and therefore equals one right angle; this makes $PA$ perpendicular to radius $OA$ , i.e. a tangent.

এই অধ্যায়ের আরও প্রশ্ন

C-08-Q201From an external point of a circle, the maximum number of tangents that can be drawn is—
C-08-Q202To construct the circumcircle of , one draws—
C-08-Q203The circumcentre of an acute-angled triangle lies—
C-08-Q204The circumcentre of a right-angled triangle lies—
C-08-Q205The circumcentre of an obtuse-angled triangle lies—
C-08-Q206To construct the incircle of , one draws—
C-08-Q207The incentre is equidistant from—
C-08-Q208From the incentre , the radius of the incircle is the perpendicular distance from to—
C-08-Q209An ex-circle of a triangle touches—
C-08-Q210The number of ex-circles of a triangle is—

Circle — সব প্রশ্ন দেখুন (231টি) →

In Construction 8, $\angle PAO = 1$ right angle because—

\triangle PAO

is equilateral

bit is the angle inscribed in the semicircle of the auxiliary circle

cof SSS congruence

dof an arbitrary choice

In Construction 8, ∠PAO=1\angle PAO = 1∠PAO=1 right angle because—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In Construction 8, ∠PAO=1\angle PAO = 1∠PAO=1 right angle because—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In Construction 8, $\angle PAO = 1$ right angle because—

In Construction 8, $\angle PAO = 1$ right angle because—