C-08-Q131mediumsingle_mcq

If $\angle PQR$ of cyclic quadrilateral $PQRS$ is $110^{\circ}$ , then $\angle PSR$ is—

$\angle PQR$ and $\angle PSR$ are opposite angles of the cyclic quadrilateral, so $\angle PSR = 180^{\circ} - 110^{\circ} = 70^{\circ}$ .

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এই অধ্যায়ের আরও প্রশ্ন

C-08-Q132Theorem 24 states that if two opposite angles of a quadrilateral are supplementary, then the four vertices are
C-08-Q133Theorem 24 is the converse of—
C-08-Q134The proof of Theorem 24 begins by assuming a circle through three of the four vertices and seeking a contradic
C-08-Q135In the proof, is the second intersection point of side with the auxiliary circle through . We deduce , which c
C-08-Q136The conclusion of Theorem 24 is that—
C-08-Q137The internal and external bisectors of and of meeting at and make —
C-08-Q138In Exercise 8.3 Q2, four points are—
C-08-Q139If chords of a circle with centre meet at right angles inside the circle, then equals—
C-08-Q140In a cyclic quadrilateral with opposite angles supplementary and bisecting , we have—

90^{\circ}

55^{\circ}

∘

−

110∘=

70∘