C-08-Q116mediumsingle_mcq

The locus of points $P$ such that $\angle APB = 90^{\circ}$ for a fixed segment $AB$ is—

aa straight line
ba circle with $AB$ as diameter (excluding $A,B$ )
ca parabola
dan ellipse

ব্যাখ্যা

By Thales' theorem and its converse, $\angle APB=90^\circ$ exactly when $P$ lies on the circle having $AB$ as diameter. The points $A,B$ themselves are excluded since no angle is formed there.

এই অধ্যায়ের আরও প্রশ্ন

C-08-Q117is a cyclic quadrilateral with diagonals meeting at . Then equals—
C-08-Q118In a cyclic quadrilateral , if right angle, then which three points are collinear?
C-08-Q119The oblique sides of a cyclic trapezium are—
C-08-Q120In a circle with centre and cm, the perimeter of the (cyclic) figure depends on—
C-08-Q121In Exercise 8.2 Q5, two chords and intersect at . Then and are—
C-08-Q122A quadrilateral having all four vertices on a circle is called—
C-08-Q123Theorem 23 states that the sum of the two opposite angles of a cyclic quadrilateral is—
C-08-Q124In a cyclic quadrilateral , equals—
C-08-Q125In a cyclic quadrilateral , equals—
C-08-Q126The proof of Theorem 23 uses—

Circle — সব প্রশ্ন দেখুন (231টি) →

The locus of points $P$ such that $\angle APB = 90^{\circ}$ for a fixed segment $AB$ is—

aa straight line

ba circle with

AB

as diameter (excluding

A,B

)

ca parabola

dan ellipse

ব্যাখ্যা

By Thales' theorem and its converse, $\angle APB=90^\circ$ exactly when $P$ lies on the circle having $AB$ as diameter. The points $A,B$ themselves are excluded since no angle is formed there.

The locus of points PPP such that ∠APB=90∘\angle APB = 90^{\circ}∠APB=90∘ for a fixed segment ABABAB is—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

The locus of points PPP such that ∠APB=90∘\angle APB = 90^{\circ}∠APB=90∘ for a fixed segment ABABAB is—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

The locus of points $P$ such that $\angle APB = 90^{\circ}$ for a fixed segment $AB$ is—

The locus of points $P$ such that $\angle APB = 90^{\circ}$ for a fixed segment $AB$ is—