C-11-Q139mediummulti_combo_mcq

If $x:y = 2:1$ and $y:z = 2:1$ , which combination is correct?

$x, y, z$ are continued proportional
$z:x = 1:4$
$y^2 + 2x = 4yz$

ai and ii
bi and iii
cii and iii
di, ii and iii

ব্যাখ্যা

Combining gives $x:y:z = 4:2:1$ . Then $y^2 = 4 = xz$ (i is true) and $z:x = 1:4$ (ii is true), but $y^2+2x = 12 \neq 4yz = 8$ , so iii fails — only i and ii hold.

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Algebraic Ratio and Proportion — সব প্রশ্ন দেখুন (180টি) →

If $x:y = 2:1$ and $y:z = 2:1$ , which combination is correct?

x, y, z

are continued proportional

z:x = 1:4

y^2 + 2x = 4yz

ai and ii

bi and iii

cii and iii

di, ii and iii

ব্যাখ্যা

Combining gives $x:y:z = 4:2:1$ . Then $y^2 = 4 = xz$ (i is true) and $z:x = 1:4$ (ii is true), but $y^2+2x = 12 \neq 4yz = 8$ , so iii fails — only i and ii hold.

If x:y=2:1x:y = 2:1x:y=2:1 and y:z=2:1y:z = 2:1y:z=2:1, which combination is correct?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

If x:y=2:1x:y = 2:1x:y=2:1 and y:z=2:1y:z = 2:1y:z=2:1, which combination is correct?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

If $x:y = 2:1$ and $y:z = 2:1$ , which combination is correct?

If $x:y = 2:1$ and $y:z = 2:1$ , which combination is correct?