C-03-Q188mediumsingle_mcq

Divide Tk 260 among A, B, C such that $2A = 3B = 4C$ . Shares are—

aTk 120, 80, 60
bTk 130, 90, 40
cTk 100, 80, 80
dTk 80, 100, 80

ব্যাখ্যা

Setting $2A = 3B = 4C = k$ gives $A = \dfrac{k}{2}$ , $B = \dfrac{k}{3}$ , $C = \dfrac{k}{4}$ . Their sum $\dfrac{13k}{12} = 260$ gives $k = 240$ , so the shares are Tk 120, 80, and 60.

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Algebraic Expressions — সব প্রশ্ন দেখুন (219টি) →

Divide Tk 260 among A, B, C such that $2A = 3B = 4C$ . Shares are—

aTk 120, 80, 60

bTk 130, 90, 40

cTk 100, 80, 80

dTk 80, 100, 80

ব্যাখ্যা

Setting $2A = 3B = 4C = k$ gives $A = \dfrac{k}{2}$ , $B = \dfrac{k}{3}$ , $C = \dfrac{k}{4}$ . Their sum $\dfrac{13k}{12} = 260$ gives $k = 240$ , so the shares are Tk 120, 80, and 60.

Divide Tk 260 among A, B, C such that 2A=3B=4C2A = 3B = 4C2A=3B=4C. Shares are—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Divide Tk 260 among A, B, C such that 2A=3B=4C2A = 3B = 4C2A=3B=4C. Shares are—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Divide Tk 260 among A, B, C such that $2A = 3B = 4C$ . Shares are—

Divide Tk 260 among A, B, C such that $2A = 3B = 4C$ . Shares are—