C-03-Q171mediumsingle_mcq

Same setup. Speed of current = ?

a $\dfrac{x}{2}\left(\dfrac{1}{t_2} - \dfrac{1}{t_1}\right)$
b $\dfrac{x}{2}\left(\dfrac{1}{t_1} + \dfrac{1}{t_2}\right)$
c $\dfrac{x}{2}\left(\dfrac{1}{t_1} - \dfrac{1}{t_2}\right)$
d $x(t_1 - t_2)$

ব্যাখ্যা

Subtracting upstream from downstream, $(b+c)-(b-c)=2c$ , so $c = \dfrac{x}{2}\left(\dfrac{1}{t_2}-\dfrac{1}{t_1}\right)$ . The current is half the difference of the downstream and upstream speeds.

এই অধ্যায়ের আরও প্রশ্ন

Algebraic Expressions — সব প্রশ্ন দেখুন (219টি) →

Same setup. Speed of current = ?

\dfrac{x}{2}\left(\dfrac{1}{t_2} - \dfrac{1}{t_1}\right)

\dfrac{x}{2}\left(\dfrac{1}{t_1} + \dfrac{1}{t_2}\right)

\dfrac{x}{2}\left(\dfrac{1}{t_1} - \dfrac{1}{t_2}\right)

x(t_1 - t_2)

ব্যাখ্যা

Subtracting upstream from downstream, $(b+c)-(b-c)=2c$ , so $c = \dfrac{x}{2}\left(\dfrac{1}{t_2}-\dfrac{1}{t_1}\right)$ . The current is half the difference of the downstream and upstream speeds.