C-18-Q039mediumsingle_mcq

Running the textbook code with `count=1`, `while (count<=3): print('ICT'); count=count+1` prints:

aICT once
bICT twice
cICT three times
dICT four times

ব্যাখ্যা

With count starting at 1 and incrementing by 1, the body runs for count = 1, 2, and 3, then stops when count becomes 4. So print('ICT') executes exactly three times.

এই অধ্যায়ের আরও প্রশ্ন

C-18-Q040Which line in the loop is responsible for actually showing the word ICT on screen?
C-18-Q041If the condition were changed to while (count<=5) with the same counter logic, the text ICT would be displayed
C-18-Q042If the counter increment count=count+1 is removed from the while loop, the code will:
C-18-Q043Which Python comparison operator allows the counter value 3 itself to enter the loop body in while (count<=3)?
C-18-Q044To convert the same task to a for loop, an equivalent header is:
C-18-Q045The sum of all positive integers from 1 to 100 (the result of the textbook program) is:
C-18-Q046In the textbook sum program, the accumulator variable is initialized as:
C-18-Q047The counter variable in the sum program is initialized as:
C-18-Q048Inside the loop, the value of sum is updated with the line:
C-18-Q049The loop condition used to add numbers up to 100 is:

Problem Solving through Programming (Nested Loops, While, Continue and Break) — সব প্রশ্ন দেখুন (103টি) →

Running the textbook code with count=1, while (count<=3): print('ICT'); count=count+1 prints:

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Running the textbook code with count=1, while (count<=3): print('ICT'); count=count+1 prints:

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Running the textbook code with `count=1`, `while (count<=3): print('ICT'); count=count+1` prints:

Running the textbook code with `count=1`, `while (count<=3): print('ICT'); count=count+1` prints: