C-08-Q161mediumsingle_mcqIn 0<θ<2π0 < \theta < 2\pi0<θ<2π, the solutions of sin2θ−cos2θ=cosθ\sin^{2}\theta - \cos^{2}\theta = \cos\thetasin2θ−cos2θ=cosθ are —aπ3, π, 5π3\dfrac{\pi}{3},\ \pi,\ \dfrac{5\pi}{3}3π, π, 35πbπ4, π2, π\dfrac{\pi}{4},\ \dfrac{\pi}{2},\ \pi4π, 2π, πc0, π0,\ \pi0, πdπ6, π, 11π6\dfrac{\pi}{6},\ \pi,\ \dfrac{11\pi}{6}6π, π, 611π