C-08-Q117mediumsingle_mcqWith tanA=−512\tan A = -\dfrac{5}{12}tanA=−125 (opposite sign with cosA\cos AcosA), cosA\cos AcosA equals —a513\dfrac{5}{13}135b−513-\dfrac{5}{13}−135c1213\dfrac{12}{13}1312d−1213-\dfrac{12}{13}−1312