C-01-Q055mediumsingle_mcqDistributive law: A∩(B∪C)A \cap (B \cup C)A∩(B∪C) = ?a(A∩B)∪(A∩C)(A \cap B) \cup (A \cap C)(A∩B)∪(A∩C)b(A∪B)∩(A∪C)(A \cup B) \cap (A \cup C)(A∪B)∩(A∪C)cA∪B∪CA \cup B \cup CA∪B∪Cd(A∩B)∩(A∩C)(A \cap B) \cap (A \cap C)(A∩B)∩(A∩C)