C-12-Q084mediumsingle_mcqD, E, F are the midpoints of sides BC, CA, AB of △ABC\triangle ABC△ABC respectively. Then AD⃗+BE⃗+CF⃗=\vec{AD}+\vec{BE}+\vec{CF}=AD+BE+CF=aAB⃗\vec{AB}ABbBC⃗\vec{BC}BCc0⃗\vec{0}0dAB⃗+BC⃗+CA⃗\vec{AB}+\vec{BC}+\vec{CA}AB+BC+CA