C-07-Q064mediumsingle_mcqFor the same series with x=32x = \dfrac{3}{2}x=23, the sum of first 101010 terms is —a13(1−1410)\dfrac{1}{3}\left(1 - \dfrac{1}{4^{10}}\right)31(1−4101)b14(1−1410)\dfrac{1}{4}\left(1 - \dfrac{1}{4^{10}}\right)41(1−4101)c1410\dfrac{1}{4^{10}}4101d13\dfrac{1}{3}31