C-07-Q009mediumsingle_mcqThe general term of the sequence 12,15,110,117,…\dfrac{1}{2}, \dfrac{1}{5}, \dfrac{1}{10}, \dfrac{1}{17}, \ldots21,51,101,171,… is —a1n+1\dfrac{1}{n+1}n+11b12n\dfrac{1}{2n}2n1c1n2+1\dfrac{1}{n^2 + 1}n2+11d12n−1\dfrac{1}{2n - 1}2n−11