C-03-Q030mediumsingle_mcqIn △ABC\triangle ABC△ABC with sides a,b,ca, b, ca,b,c opposite to vertices A,B,CA, B, CA,B,C and medians d,e,fd, e, fd,e,f from A,B,CA, B, CA,B,C respectively, d2=d^2 =d2=a2(b2+c2)−a24\dfrac{2(b^2+c^2) - a^2}{4}42(b2+c2)−a2b2(a2+c2)−b24\dfrac{2(a^2+c^2) - b^2}{4}42(a2+c2)−b2c2(a2+b2)−c24\dfrac{2(a^2+b^2) - c^2}{4}42(a2+b2)−c2da2+b2+c24\dfrac{a^2+b^2+c^2}{4}4a2+b2+c2