C-03-Q008mediumsingle_mcqIn right △ABC\triangle ABC△ABC with ∠A=90°\angle A = 90°∠A=90°, BC2=BC^2 =BC2=aAB2−AC2AB^2 - AC^2AB2−AC2bAB⋅ACAB \cdot ACAB⋅ACcAB2+AC2AB^2 + AC^2AB2+AC2d2AB⋅AC2 AB \cdot AC2AB⋅AC