C-09-Q148mediumsingle_mcqIf x,y,z≠0x, y, z \neq 0x,y,z=0, ax=by=cza^x = b^y = c^zax=by=cz and b2=acb^2 = acb2=ac, which is correct?a1x+1y=2z\dfrac{1}{x} + \dfrac{1}{y} = \dfrac{2}{z}x1+y1=z2b1x+1z=2y\dfrac{1}{x} + \dfrac{1}{z} = \dfrac{2}{y}x1+z1=y2c1y+1z=2x\dfrac{1}{y} + \dfrac{1}{z} = \dfrac{2}{x}y1+z1=x2d1x+1y=1z\dfrac{1}{x} + \dfrac{1}{y} = \dfrac{1}{z}x1+y1=z1