C-09-Q088mediumsingle_mcqloga(M⋅N)\log_a (M \cdot N)loga(M⋅N) equals:alogaM⋅logaN\log_a M \cdot \log_a NlogaM⋅logaNblogaM+logaN\log_a M + \log_a NlogaM+logaNclogaM−logaN\log_a M - \log_a NlogaM−logaNdloga(M+N)\log_a (M+N)loga(M+N)