C-05-Q092mediumsingle_mcqThe solutions of 8⋅27x=4y, 9x⋅3xy=138 \cdot 27^x = 4^y,\ 9^x \cdot 3^{xy} = \dfrac{1}{3}8⋅27x=4y, 9x⋅3xy=31 are —a(−1,1)(-1, 1)(−1,1) and (3,−3)(3, -3)(3,−3)b(1,−1)(1, -1)(1,−1) and (−3,3)(-3, 3)(−3,3)c(0,0)(0, 0)(0,0) onlyd(2,1)(2, 1)(2,1) and (1,2)(1, 2)(1,2)