C-05-Q027mediumsingle_mcqThe roots of 2x2+7x−1=02x^2 + 7x - 1 = 02x2+7x−1=0 are —a−7±574\dfrac{-7 \pm \sqrt{57}}{4}4−7±57b7±574\dfrac{7 \pm \sqrt{57}}{4}47±57c−7±414\dfrac{-7 \pm \sqrt{41}}{4}4−7±41d−7±494\dfrac{-7 \pm \sqrt{49}}{4}4−7±49