C-02-Q088mediumsingle_mcqThe partial fraction setup for x(x−1)(x2+4)\dfrac{x}{(x-1)(x^2 + 4)}(x−1)(x2+4)x is:aAx−1+Bx2+4\dfrac{A}{x-1} + \dfrac{B}{x^2+4}x−1A+x2+4BbAx−1+Bx+Cx2+4\dfrac{A}{x-1} + \dfrac{Bx + C}{x^2+4}x−1A+x2+4Bx+CcAx+Bx−1+Cx2+4\dfrac{Ax + B}{x-1} + \dfrac{C}{x^2+4}x−1Ax+B+x2+4CdAx−1+Bxx2+4\dfrac{A}{x-1} + \dfrac{Bx}{x^2+4}x−1A+x2+4Bx