C-02-Q063mediumsingle_mcqA∪(B∩C)=?A \cup (B \cap C) = ?A∪(B∩C)=?a(A∪B)∩(A∪C)(A \cup B) \cap (A \cup C)(A∪B)∩(A∪C)b(A∩B)∪(A∩C)(A \cap B) \cup (A \cap C)(A∩B)∪(A∩C)cA∩B∩CA \cap B \cap CA∩B∩CdA∪B∪CA \cup B \cup CA∪B∪C