C-04-Q099mediumsingle_mcqa1/2⋅a1/3=?a^{1/2} \cdot a^{1/3} = ?a1/2⋅a1/3=?aa5/6a^{5/6}a5/6ba1/6a^{1/6}a1/6ca2/3a^{2/3}a2/3da1/5a^{1/5}a1/5