C-11-Q049mediumsingle_mcqab=cd=ef=gh\dfrac{a}{b}=\dfrac{c}{d}=\dfrac{e}{f}=\dfrac{g}{h}ba=dc=fe=hg হলে প্রতিটি অনুপাত সমান —aa+c+e+gb+d+f+h\dfrac{a+c+e+g}{b+d+f+h}b+d+f+ha+c+e+gbabcgbdfh\dfrac{abcg}{bdfh}bdfhabcgca−c−e−gb+d+f+h\dfrac{a-c-e-g}{b+d+f+h}b+d+f+ha−c−e−gda+b+c+de+f+g+h\dfrac{a+b+c+d}{e+f+g+h}e+f+g+ha+b+c+d